0.3x^2+7x-100=0

Solution for 0.3x^2+7x-100=0 equation:

0.3x^2+7x-100=0

a = 0.3; b = 7; c = -100;
Δ = b2-4ac
Δ = 72-4·0.3·(-100)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*0.3}=\frac{-20}{0.6}
=-33+0.2/0.6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*0.3}=\frac{6}{0.6}
=10
$